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PHP
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Remember me option using PHP Cookie | $_COOKIE

How can we do remember me to function fully with cookies under login.php?

PHP
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can we set cookies and have sweet alert redirect at the same time?

Hi Manfred, As per my register.php screenshot, how can we set cookies and have sweet alert redirect at the same time?

PHP
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How can i create a proper message text area with input tag to store php value?



     <form method="POST">
        <div class="input_field">
         <label for="comments" class="label">Message: <b class="error">*</b></label>
         <input type="text" name="comments" class="form-control" value="<?php echo $comments; ?>"> 
         </input>
        </div>
        </form>
        
        
        VS 
        
         <textarea id="form_message" name="message" class="form-control" placeholder="Message for me *" rows="4" required="required" data-error="Please,leave us a message."></textarea>

Hi there, i am using php and HTML to do up a contact us form. I understand that with the <textarea> header I can give a nice message box where the wordings doesn't get hide behind the screen as it's wrapped nicely with sufficient space. However, I would want to keep the value of the form intact on their message to allow user to edit the form before submitting it again. How can I achieve the textarea box with an input tag?    

PHP
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Isset function on echoing out alerts

Hi all,


I have the above codes in the image but the alert/echo doesn't work. How do I go about fixing it?

PHP
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Redirect navbar links to another page via php

Hi admins,


How can i redirect my navbar link to another page of PHP?
<li><a href="ContactUs.html">Contact Us</a></li>

thanks in advance.

PHP
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Config error at my output page

There is an error message when i do not fill in the compulsory fields.


Warning: Undefined array key "userWebsite" in C:\MAMP\htdocs\assignment2\output.php on line 11
Warning: Undefined array key "userAge" in C:\MAMP\htdocs\assignment2\output.php on line 12
Warning: Undefined array key "userComment" in C:\MAMP\htdocs\assignment2\output.php on line 14


my current code at my output page is 

<code>
<?php
include('core/config.php');

$userName = $_COOKIE["userName"];
$userEmail = $_COOKIE["userEmail"];
$userPhone = $_COOKIE["userPhone"];
$userWebsite = $_COOKIE["userWebsite"];
$userAge = $_COOKIE["userAge"];
$userGender = $_COOKIE["userGender"];
$userComment = $_COOKIE["userComment"];
$isLoggedIn = $_COOKIE["isLoggedIn"];

if($_COOKIE["isLoggedIn"] == 0){
    header("location: index.php");
    exit();
}
?>

<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>

<body>
    <h1> Hello <?php echo $userName; ?> </h1>
    <h3><?php echo $userEmail;?></h3>
    <h3><?php echo $userPhone;?></h3>
    <h3><?php echo $userWebsite;?></h3>
    <h3><?php echo $userAge;?></h3>
    <h3><?php echo $userGender;?></h3>
    <h3><?php echo $userComment;?></h3>

    <a href="logout.php"> Logout </a>
</body>

</html>
</code>

PHP
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PHP : Redirect user back to LoggedIn page after logging in

I have problem coding for SESSION approach using in index.php (login page) 

to redirect user into 
output.php (Dashboard page) after logging in.

For example, 
After logging in, User accidentally close browser while in output.php url and forgot output.php url.
User open up index.php url and it redirect user back to output.php url.

However,  my code for 
deny access to the user 
and
redirected to login page when they haven't sign up when typed index.php (login page) url works just fine.

The recording was taught the COOKIE approach instead of SESSION approach.

Although it is not in the assignment requirement to redirect to output.php even after logging in, as it only require to redirect user back to index.php if they attempt to reach output.php without logging in, I like to know more using the SESSION approach.


PHP
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Is there a difference when deleting cookies using the PHP setcookie() Function by using "0" or "false" as Boolean values instead of using an empty string (like this " ")?

Hello everyone!


My question is on deleting a cookie using the setcookie() function in PHP, when the first argument is boolean (aka true/false).

In the logout.php file, the following code is used and it works (note the second argument which is an empty string " " to mean the first argument "isLoggedIn" is now valueless:


// Delete the cookie for isLoggedIn
setcookie("isLoggedIn", "", time() - 3600); // Delete the cookie for isLoggedIn


However, since in the login.php file, we set cookies as such:


// Set cookies
setcookie("isLoggedIn", true, time() + (86400 * 30));


where the "isLoggedIn" is a boolean (with "true" as the argument),

will it make a difference if in the logout.php file, we do this (note the second argument "0"):


setcookie("isLoggedIn", "0", time() - 3600); // Delete the cookie for isLoggedIn


OR this (note the second argument "false"):


setcookie("isLoggedIn", "false", time() - 3600); // Delete the cookie for isLoggedIn


instead?

When I tested it, both the alternatives work the exact same way.

But my question is, is there any other differences between the first and the other two methods? Or is it just a matter of personal choice/company culture?

Thanks in advance!

PHP
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How to set Gender Male to show the word "Male" when I echo it from radio button?

Hello my code is 

<code>
<div class class="btn-group btn-group-toggle" data-toggle="buttons">
            <label class="btn">
                <input type="radio" name="gender" id="option1" autocomplete="off"> Male
            </label>
            <label class="btn ">
                <input type="radio" name="gender" id="option2" autocomplete="off"> Female
            </label>
            <div id="emailHelp" class="form-text">Required</div>
</code>

and cookies is set 

<code>
setcookie("userGender", $gender, time()+ (86400));
</code>

Then the output page is 

<code>
$userGender = $_COOKIE["userGender"];
</code>

When i am in my output page the gender is show as "on" >??? I dont see any word on. 

PHP
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Multiple Files Upload

Please advise if any of the following validations may be improved, and/or any part of the codes may be shortened?

<?php

// Check if form was submitted
if(isset($_POST['submit'])) {

// Configure upload directory and allowed file types
$upload_dir = 'uploads/'.DIRECTORY_SEPARATOR;
$allowed_types = array('jpg', 'png', 'jpeg', 'gif');
// Define maxsize for files 64MB, as per php.ini settings
$maxsize = 64 * 1024 * 1024;

// Checks if user sent an empty form
if(!empty(array_filter($_FILES['files']['name']))) {

// Loop through each file in files[] array
foreach ($_FILES['files']['tmp_name'] as $key =--> $value) {
$file_tmpname = $_FILES['files']['tmp_name'][$key];
$file_name = $_FILES['files']['name'][$key];
$file_size = $_FILES['files']['size'][$key];
$file_ext = pathinfo($file_name, PATHINFO_EXTENSION);

// Set upload file path
$filepath = $upload_dir.$file_name;

// Check file type is allowed or not
if(in_array(strtolower($file_ext), $allowed_types)) {

// Verify file size - 2MB max
if ($file_size &gt; $maxsize)
echo "Error: File size is larger than the allowed limit.";

// If file with name already exist then append time in
// front of name of the file to avoid overwriting of file
if(file_exists($filepath)) {
$filepath = $upload_dir.time().$file_name;
if( move_uploaded_file($file_tmpname, $filepath)) {
echo "{$file_name} successfully uploaded <br>";
}
else {
echo "Error uploading {$file_name} <br>";
}
}
else {
if( move_uploaded_file($file_tmpname, $filepath)) {
echo "{$file_name} successfully uploaded <br>";
}
else {
echo "Error uploading {$file_name} <br>";
}
}
}
else {
// If file extension not valid
echo "Error uploading {$file_name} ";
echo "({$file_ext} file type is not allowed)<br>";
}
}
}
else {
// If no files selected
echo "No files selected.";
}
}
?>


    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Select and upload multiple files to the server</title>


    
<!-- multipart/form-data ensures that form
data is going to be encoded as MIME data -->

<h2>Upload Files</h2>
        <p>Select files to upload:
<!-- name of the input fields are going to
be used in our php script-->
<input type="file" name="files[]" multiple="">
<br><br>
<input type="submit" name="submit" value="Upload">
</p>

PHP
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undefined array key and variable


include('core/config.php');
include('core/db.php');
include('core/functions.php');

isNotLoggedIn(); //redirect to login page
$userID = $_COOKIE["userID"];

// Query user info from DB
$userQuery = DB::query("SELECT * FROM users WHERE userID = %i", $userID);
foreach($userQuery as $userResult){
$userEmail = $userResult["userEmail"];
$userPermission = $userResult["userPermission"];
}

// Setting permission text
if($userPermission == 1){
$userPermissionText = "Admin";
}else if($userPermission == 0){
$userPermissionText = "User";
}


Any idea why is this error popping up?

Python
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Django Admin interface- Recent object title and object name doesn't work

I have tried this method:
1) python manage.py makemigrations >>No changes detected
2) python manage.py migrate>>
Operations to perform:
Apply all migrations: admin, auth, contenttypes, menu, sessions
Running migrations:
No migrations to apply.
3) CTRL + SHIFT + R to hard reset http://127.0.0.1:8000/admin/
4) Adding a new menu via http://127.0.0.1:8000/admin/menu/menu/add/

#models.py page
from django.db import models

class Menu(models.Model):
productName = models.CharField(max_length=255)
price = models.FloatField()
image_url = models.CharField(max_length=2083)
category = models.CharField(max_length=255)

def _str_ (self):
return self.product_name


#admin.py page

from django.contrib import admin
from .models import Menu

class MenuAdmin(admin.ModelAdmin):
list_display =('productName', 'price','image_url','category')

admin.site.register(Menu, MenuAdmin)

Python
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How to change Display Name of an Object in Django Admin interface?

Whenever an instance of model is created in Django, it displays the object as ModelName Object(1).

How do we make changes to our code so that it changes the display name to its own name?

Python
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How to use objects.filters in Django?

Hello. For Assignment 1 last question,

Create respective categories pages "/menu/{category_name}" to display all menu items from the database according to their categories
Categories to use:
Starters
Mains
Beverages
Desserts

I have the page up and tested with Http response and I have an idea of using object.filter() to do the separation of item by category.

I have a problem with the code as i tried it multiple way of putting it as below


def Starters(request):
starter = Menu.objects.filters(Menu_menu_category=Starters)
return render(request, 'index.html', {'Menu': starter})


and also


def Starters(request):
starter = Menu.objects.filters(category=Starters)
return render(request, 'index.html', {'Menu': starter})


How do make that function to pick up my data from the table column?

PHP
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forEach-Loop

//When i print out the code below, it give ms only 1 result . Not sure why.//

$bikes = array("Honda"=>"exMotion", "Honda"=>"Adv150", "Honda"=>"NC750");

foreach($bikes as $bike => $model) {
echo "$bike = $model
";
}